7(u+3)=2(u-1)=12

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Solution for 7(u+3)=2(u-1)=12 equation: 



7(u+3)=2(u-1)=12

We move all terms to the left:

7(u+3)-(2(u-1))=0

We multiply parentheses

7u-(2(u-1))+21=0



We calculate terms in parentheses: -(2(u-1)), so:

2(u-1)

We multiply parentheses

2u-2

Back to the equation:

-(2u-2)



We get rid of parentheses

7u-2u+2+21=0

We add all the numbers together, and all the variables

5u+23=0

We move all terms containing u to the left, all other terms to the right

5u=-23

u=-23/5

u=-4+3/5

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