3(2c+8)=10c+28

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Solution for 3(2c+8)=10c+28 equation: 



3(2c+8)=10c+28

We move all terms to the left:

3(2c+8)-(10c+28)=0

We multiply parentheses

6c-(10c+28)+24=0

We get rid of parentheses

6c-10c-28+24=0

We add all the numbers together, and all the variables

-4c-4=0

We move all terms containing c to the left, all other terms to the right

-4c=4

c=4/-4

c=-1

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