10-(n-8)=6(n+2)

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Solution for 10-(n-8)=6(n+2) equation: 



10-(n-8)=6(n+2)

We move all terms to the left:

10-(n-8)-(6(n+2))=0

We get rid of parentheses

-n-(6(n+2))+8+10=0



We calculate terms in parentheses: -(6(n+2)), so:

6(n+2)

We multiply parentheses

6n+12

Back to the equation:

-(6n+12)



We add all the numbers together, and all the variables

-1n-(6n+12)+18=0

We get rid of parentheses

-1n-6n-12+18=0

We add all the numbers together, and all the variables

-7n+6=0

We move all terms containing n to the left, all other terms to the right

-7n=-6

n=-6/-7

n=6/7

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