3(2c+5)=12+3(c+4)

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Solution for 3(2c+5)=12+3(c+4) equation: 



3(2c+5)=12+3(c+4)

We move all terms to the left:

3(2c+5)-(12+3(c+4))=0

We multiply parentheses

6c-(12+3(c+4))+15=0



We calculate terms in parentheses: -(12+3(c+4)), so:

12+3(c+4)

determiningTheFunctionDomain
3(c+4)+12

We multiply parentheses

3c+12+12

We add all the numbers together, and all the variables

3c+24

Back to the equation:

-(3c+24)



We get rid of parentheses

6c-3c-24+15=0

We add all the numbers together, and all the variables

3c-9=0

We move all terms containing c to the left, all other terms to the right

3c=9

c=9/3

c=3

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