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2(3x+1)=4(x+3)
We move all terms to the left:
2(3x+1)-(4(x+3))=0
We multiply parentheses
6x-(4(x+3))+2=0
We calculate terms in parentheses: -(4(x+3)), so:We get rid of parentheses
4(x+3)
We multiply parentheses
4x+12
Back to the equation:
-(4x+12)
6x-4x-12+2=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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