3(2b+9)=2(b+3)

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Solution for 3(2b+9)=2(b+3) equation:



3(2b+9)=2(b+3)
We move all terms to the left:
3(2b+9)-(2(b+3))=0
We multiply parentheses
6b-(2(b+3))+27=0
We calculate terms in parentheses: -(2(b+3)), so:
2(b+3)
We multiply parentheses
2b+6
Back to the equation:
-(2b+6)
We get rid of parentheses
6b-2b-6+27=0
We add all the numbers together, and all the variables
4b+21=0
We move all terms containing b to the left, all other terms to the right
4b=-21
b=-21/4
b=-5+1/4

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