33-(2c-4)=2(c+7)+c

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Solution for 33-(2c-4)=2(c+7)+c equation: 



33-(2c-4)=2(c+7)+c

We move all terms to the left:

33-(2c-4)-(2(c+7)+c)=0

We get rid of parentheses

-2c-(2(c+7)+c)+4+33=0



We calculate terms in parentheses: -(2(c+7)+c), so:

2(c+7)+c

We add all the numbers together, and all the variables

c+2(c+7)

We multiply parentheses

c+2c+14

We add all the numbers together, and all the variables

3c+14

Back to the equation:

-(3c+14)



We add all the numbers together, and all the variables

-2c-(3c+14)+37=0

We get rid of parentheses

-2c-3c-14+37=0

We add all the numbers together, and all the variables

-5c+23=0

We move all terms containing c to the left, all other terms to the right

-5c=-23

c=-23/-5

c=4+3/5

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