3(2a-1)+2(a+4)+5a+6=50

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Solution for 3(2a-1)+2(a+4)+5a+6=50 equation: 



3(2a-1)+2(a+4)+5a+6=50

We move all terms to the left:

3(2a-1)+2(a+4)+5a+6-(50)=0

We add all the numbers together, and all the variables

5a+3(2a-1)+2(a+4)-44=0

We multiply parentheses

5a+6a+2a-3+8-44=0

We add all the numbers together, and all the variables

13a-39=0

We move all terms containing a to the left, all other terms to the right

13a=39

a=39/13

a=3

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