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3(2a+5)=4(3a-5)
We move all terms to the left:
3(2a+5)-(4(3a-5))=0
We multiply parentheses
6a-(4(3a-5))+15=0
We calculate terms in parentheses: -(4(3a-5)), so:We get rid of parentheses
4(3a-5)
We multiply parentheses
12a-20
Back to the equation:
-(12a-20)
6a-12a+20+15=0
We add all the numbers together, and all the variables
-6a+35=0
We move all terms containing a to the left, all other terms to the right
-6a=-35
a=-35/-6
a=5+5/6
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