4(3x+1)-(12x-3x)+32=-5x+(10x-10)

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Solution for 4(3x+1)-(12x-3x)+32=-5x+(10x-10) equation: 



4(3x+1)-(12x-3x)+32=-5x+(10x-10)

We move all terms to the left:

4(3x+1)-(12x-3x)+32-(-5x+(10x-10))=0

We add all the numbers together, and all the variables

4(3x+1)-(+9x)-(-5x+(10x-10))+32=0

We multiply parentheses

12x-(+9x)-(-5x+(10x-10))+4+32=0

We get rid of parentheses

12x-9x-(-5x+(10x-10))+4+32=0



We calculate terms in parentheses: -(-5x+(10x-10)), so:

-5x+(10x-10)

We get rid of parentheses

-5x+10x-10

We add all the numbers together, and all the variables

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

3x-(5x-10)+36=0

We get rid of parentheses

3x-5x+10+36=0

We add all the numbers together, and all the variables

-2x+46=0

We move all terms containing x to the left, all other terms to the right

-2x=-46

x=-46/-2

x=+23

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