3(2C+3)=5(c-7)+12

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Solution for 3(2C+3)=5(c-7)+12 equation: 



3(2+3)=5(C-7)+12

We move all terms to the left:

3(2+3)-(5(C-7)+12)=0

We add all the numbers together, and all the variables

-(5(C-7)+12)+35=0



We calculate terms in parentheses: -(5(C-7)+12), so:

5(C-7)+12

We multiply parentheses

5C-35+12

We add all the numbers together, and all the variables

5C-23

Back to the equation:

-(5C-23)



We get rid of parentheses

-5C+23+35=0

We add all the numbers together, and all the variables

-5C+58=0

We move all terms containing C to the left, all other terms to the right

-5C=-58

C=-58/-5

C=11+3/5

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