((4x+1)+(x+3))=22

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Solution for ((4x+1)+(x+3))=22 equation: 



((4x+1)+(x+3))=22

We move all terms to the left:

((4x+1)+(x+3))-(22)=0



We calculate terms in parentheses: +((4x+1)+(x+3)), so:

(4x+1)+(x+3)

We get rid of parentheses

4x+x+1+3

We add all the numbers together, and all the variables

5x+4

Back to the equation:

+(5x+4)



We get rid of parentheses

5x+4-22=0

We add all the numbers together, and all the variables

5x-18=0

We move all terms containing x to the left, all other terms to the right

5x=18

x=18/5

x=3+3/5

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