3(20-m)+m=100

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Solution for 3(20-m)+m=100 equation: 



3(20-m)+m=100

We move all terms to the left:

3(20-m)+m-(100)=0

We add all the numbers together, and all the variables

3(-1m+20)+m-100=0

We add all the numbers together, and all the variables

m+3(-1m+20)-100=0

We multiply parentheses

m-3m+60-100=0

We add all the numbers together, and all the variables

-2m-40=0

We move all terms containing m to the left, all other terms to the right

-2m=40

m=40/-2

m=-20

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