4=5(4x+1)+21x

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Solution for 4=5(4x+1)+21x equation: 



4=5(4x+1)+21x

We move all terms to the left:

4-(5(4x+1)+21x)=0



We calculate terms in parentheses: -(5(4x+1)+21x), so:

5(4x+1)+21x

We add all the numbers together, and all the variables

21x+5(4x+1)

We multiply parentheses

21x+20x+5

We add all the numbers together, and all the variables

41x+5

Back to the equation:

-(41x+5)



We get rid of parentheses

-41x-5+4=0

We add all the numbers together, and all the variables

-41x-1=0

We move all terms containing x to the left, all other terms to the right

-41x=1

x=1/-41

x=-1/41

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