3(2-b)/5=-3

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Solution for 3(2-b)/5=-3 equation: 



3(2-b)/5=-3

We move all terms to the left:

3(2-b)/5-(-3)=0

We add all the numbers together, and all the variables

3(-1b+2)/5-(-3)=0

We add all the numbers together, and all the variables

3(-1b+2)/5+3=0

We multiply all the terms by the denominator


3(-1b+2)+3*5=0

We add all the numbers together, and all the variables

3(-1b+2)+15=0

We multiply parentheses

-3b+6+15=0

We add all the numbers together, and all the variables

-3b+21=0

We move all terms containing b to the left, all other terms to the right

-3b=-21

b=-21/-3

b=+7

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