3(2+u)-u=4+2(u-1)

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Solution for 3(2+u)-u=4+2(u-1) equation: 



3(2+u)-u=4+2(u-1)

We move all terms to the left:

3(2+u)-u-(4+2(u-1))=0

We add all the numbers together, and all the variables

3(u+2)-u-(4+2(u-1))=0

We add all the numbers together, and all the variables

-1u+3(u+2)-(4+2(u-1))=0

We multiply parentheses

-1u+3u-(4+2(u-1))+6=0



We calculate terms in parentheses: -(4+2(u-1)), so:

4+2(u-1)

determiningTheFunctionDomain
2(u-1)+4

We multiply parentheses

2u-2+4

We add all the numbers together, and all the variables

2u+2

Back to the equation:

-(2u+2)



We add all the numbers together, and all the variables

2u-(2u+2)+6=0

We get rid of parentheses

2u-2u-2+6=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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