5p(p-8)=0

Solution for 5p(p-8)=0 equation:

5p(p-8)=0

We multiply parentheses

5p^2-40p=0

a = 5; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·5·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*5}=\frac{0}{10}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*5}=\frac{80}{10}
=8
$