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3(2+3x)=4(2x-1)
We move all terms to the left:
3(2+3x)-(4(2x-1))=0
We add all the numbers together, and all the variables
3(3x+2)-(4(2x-1))=0
We multiply parentheses
9x-(4(2x-1))+6=0
We calculate terms in parentheses: -(4(2x-1)), so:We get rid of parentheses
4(2x-1)
We multiply parentheses
8x-4
Back to the equation:
-(8x-4)
9x-8x+4+6=0
We add all the numbers together, and all the variables
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10
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