8(6b+3)=-32-4b

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Solution for 8(6b+3)=-32-4b equation: 



8(6b+3)=-32-4b

We move all terms to the left:

8(6b+3)-(-32-4b)=0

We add all the numbers together, and all the variables

8(6b+3)-(-4b-32)=0

We multiply parentheses

48b-(-4b-32)+24=0

We get rid of parentheses

48b+4b+32+24=0

We add all the numbers together, and all the variables

52b+56=0

We move all terms containing b to the left, all other terms to the right

52b=-56

b=-56/52

b=-1+1/13

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