3(2+3x)=-2(x-2x)-8

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Solution for 3(2+3x)=-2(x-2x)-8 equation: 



3(2+3x)=-2(x-2x)-8

We move all terms to the left:

3(2+3x)-(-2(x-2x)-8)=0

We add all the numbers together, and all the variables

3(3x+2)-(-2(-1x)-8)=0

We multiply parentheses

9x-(-2(-1x)-8)+6=0



We calculate terms in parentheses: -(-2(-1x)-8), so:

-2(-1x)-8

We multiply parentheses

2x-8

Back to the equation:

-(2x-8)



We get rid of parentheses

9x-2x+8+6=0

We add all the numbers together, and all the variables

7x+14=0

We move all terms containing x to the left, all other terms to the right

7x=-14

x=-14/7

x=-2

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