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3(2+3n)=2(n-1)+8
We move all terms to the left:
3(2+3n)-(2(n-1)+8)=0
We add all the numbers together, and all the variables
3(3n+2)-(2(n-1)+8)=0
We multiply parentheses
9n-(2(n-1)+8)+6=0
We calculate terms in parentheses: -(2(n-1)+8), so:We get rid of parentheses
2(n-1)+8
We multiply parentheses
2n-2+8
We add all the numbers together, and all the variables
2n+6
Back to the equation:
-(2n+6)
9n-2n-6+6=0
We add all the numbers together, and all the variables
7n=0
n=0/7
n=0
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