6(2x+3)+4x+4=55

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Solution for 6(2x+3)+4x+4=55 equation: 



6(2x+3)+4x+4=55

We move all terms to the left:

6(2x+3)+4x+4-(55)=0

We add all the numbers together, and all the variables

4x+6(2x+3)-51=0

We multiply parentheses

4x+12x+18-51=0

We add all the numbers together, and all the variables

16x-33=0

We move all terms containing x to the left, all other terms to the right

16x=33

x=33/16

x=2+1/16

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