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3(2+2a)=2(3a+3)
We move all terms to the left:
3(2+2a)-(2(3a+3))=0
We add all the numbers together, and all the variables
3(2a+2)-(2(3a+3))=0
We multiply parentheses
6a-(2(3a+3))+6=0
We calculate terms in parentheses: -(2(3a+3)), so:We get rid of parentheses
2(3a+3)
We multiply parentheses
6a+6
Back to the equation:
-(6a+6)
6a-6a-6+6=0
We add all the numbers together, and all the variables
=0
a=0/1
a=0
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