(3-2n)+7n=(n+3)3

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Solution for (3-2n)+7n=(n+3)3 equation: 



(3-2n)+7n=(n+3)3

We move all terms to the left:

(3-2n)+7n-((n+3)3)=0

We add all the numbers together, and all the variables

(-2n+3)+7n-((n+3)3)=0

We add all the numbers together, and all the variables

7n+(-2n+3)-((n+3)3)=0

We get rid of parentheses

7n-2n-((n+3)3)+3=0



We calculate terms in parentheses: -((n+3)3), so:

(n+3)3

We multiply parentheses

3n+9

Back to the equation:

-(3n+9)



We add all the numbers together, and all the variables

5n-(3n+9)+3=0

We get rid of parentheses

5n-3n-9+3=0

We add all the numbers together, and all the variables

2n-6=0

We move all terms containing n to the left, all other terms to the right

2n=6

n=6/2

n=3

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