3(2+2)=z+3/4

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Solution for 3(2+2)=z+3/4 equation: 



3(2+2)=z+3/4

We move all terms to the left:

3(2+2)-(z+3/4)=0

We add all the numbers together, and all the variables

-(+z+3/4)+34=0

We get rid of parentheses

-z+34-3/4=0

We multiply all the terms by the denominator


-z*4-3+34*4=0

We add all the numbers together, and all the variables

-z*4+133=0

Wy multiply elements

-4z+133=0

We move all terms containing z to the left, all other terms to the right

-4z=-133

z=-133/-4

z=33+1/4

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