6(y+2)+1=13y=

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Solution for 6(y+2)+1=13y= equation: 



6(y+2)+1=13y=

We move all terms to the left:

6(y+2)+1-(13y)=0

We add all the numbers together, and all the variables

-13y+6(y+2)+1=0

We multiply parentheses

-13y+6y+12+1=0

We add all the numbers together, and all the variables

-7y+13=0

We move all terms containing y to the left, all other terms to the right

-7y=-13

y=-13/-7

y=1+6/7

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