3(2+1u)-1u=4+2(1u+1)

Solution for 3(2+1u)-1u=4+2(1u+1) equation:

3(2+1u)-1u=4+2(1u+1)

We move all terms to the left:

3(2+1u)-1u-(4+2(1u+1))=0

We add all the numbers together, and all the variables

3(u+2)-1u-(4+2(u+1))=0

We add all the numbers together, and all the variables

-1u+3(u+2)-(4+2(u+1))=0

We multiply parentheses

-1u+3u-(4+2(u+1))+6=0


We calculate terms in parentheses: -(4+2(u+1)), so:

4+2(u+1)

determiningTheFunctionDomain
2(u+1)+4

We multiply parentheses

2u+2+4

We add all the numbers together, and all the variables

2u+6

Back to the equation:

-(2u+6)


We add all the numbers together, and all the variables

2u-(2u+6)+6=0

We get rid of parentheses

2u-2u-6+6=0

We add all the numbers together, and all the variables

=0

u=0/1

u=0