3(1v+2)-1v=2(1v-1)+5

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Solution for 3(1v+2)-1v=2(1v-1)+5 equation: 



3(1v+2)-1v=2(1v-1)+5

We move all terms to the left:

3(1v+2)-1v-(2(1v-1)+5)=0

We add all the numbers together, and all the variables

3(v+2)-1v-(2(v-1)+5)=0

We add all the numbers together, and all the variables

-1v+3(v+2)-(2(v-1)+5)=0

We multiply parentheses

-1v+3v-(2(v-1)+5)+6=0



We calculate terms in parentheses: -(2(v-1)+5), so:

2(v-1)+5

We multiply parentheses

2v-2+5

We add all the numbers together, and all the variables

2v+3

Back to the equation:

-(2v+3)



We add all the numbers together, and all the variables

2v-(2v+3)+6=0

We get rid of parentheses

2v-2v-3+6=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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