3(1z-4)=7z+4

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Solution for 3(1z-4)=7z+4 equation: 



3(1z-4)=7z+4

We move all terms to the left:

3(1z-4)-(7z+4)=0

We add all the numbers together, and all the variables

3(z-4)-(7z+4)=0

We multiply parentheses

3z-(7z+4)-12=0

We get rid of parentheses

3z-7z-4-12=0

We add all the numbers together, and all the variables

-4z-16=0

We move all terms containing z to the left, all other terms to the right

-4z=16

z=16/-4

z=-4

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