3(1z-2)+6=5(1z+4)

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Solution for 3(1z-2)+6=5(1z+4) equation: 



3(1z-2)+6=5(1z+4)

We move all terms to the left:

3(1z-2)+6-(5(1z+4))=0

We add all the numbers together, and all the variables

3(z-2)-(5(z+4))+6=0

We multiply parentheses

3z-(5(z+4))-6+6=0



We calculate terms in parentheses: -(5(z+4)), so:

5(z+4)

We multiply parentheses

5z+20

Back to the equation:

-(5z+20)



We add all the numbers together, and all the variables

3z-(5z+20)=0

We get rid of parentheses

3z-5z-20=0

We add all the numbers together, and all the variables

-2z-20=0

We move all terms containing z to the left, all other terms to the right

-2z=20

z=20/-2

z=-10

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