3+2(1k+1)=6+3k

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Solution for 3+2(1k+1)=6+3k equation: 



3+2(1k+1)=6+3k

We move all terms to the left:

3+2(1k+1)-(6+3k)=0

We add all the numbers together, and all the variables

2(k+1)-(3k+6)+3=0

We multiply parentheses

2k-(3k+6)+2+3=0

We get rid of parentheses

2k-3k-6+2+3=0

We add all the numbers together, and all the variables

-1k-1=0

We move all terms containing k to the left, all other terms to the right

-k=1

k=1/-1

k=-1

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