3(1y-4)=28

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Solution for 3(1y-4)=28 equation: 



3(1y-4)=28

We move all terms to the left:

3(1y-4)-(28)=0

We add all the numbers together, and all the variables

3(y-4)-28=0

We multiply parentheses

3y-12-28=0

We add all the numbers together, and all the variables

3y-40=0

We move all terms containing y to the left, all other terms to the right

3y=40

y=40/3

y=13+1/3

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