6(2-m)=9(m-4)

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Solution for 6(2-m)=9(m-4) equation:



6(2-m)=9(m-4)
We move all terms to the left:
6(2-m)-(9(m-4))=0
We add all the numbers together, and all the variables
6(-1m+2)-(9(m-4))=0
We multiply parentheses
-6m-(9(m-4))+12=0
We calculate terms in parentheses: -(9(m-4)), so:
9(m-4)
We multiply parentheses
9m-36
Back to the equation:
-(9m-36)
We get rid of parentheses
-6m-9m+36+12=0
We add all the numbers together, and all the variables
-15m+48=0
We move all terms containing m to the left, all other terms to the right
-15m=-48
m=-48/-15
m=3+1/5

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