3(1x-8)-5=9(x+2)+1

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Solution for 3(1x-8)-5=9(x+2)+1 equation: 



3(1x-8)-5=9(x+2)+1

We move all terms to the left:

3(1x-8)-5-(9(x+2)+1)=0

We add all the numbers together, and all the variables

3(x-8)-(9(x+2)+1)-5=0

We multiply parentheses

3x-(9(x+2)+1)-24-5=0



We calculate terms in parentheses: -(9(x+2)+1), so:

9(x+2)+1

We multiply parentheses

9x+18+1

We add all the numbers together, and all the variables

9x+19

Back to the equation:

-(9x+19)



We add all the numbers together, and all the variables

3x-(9x+19)-29=0

We get rid of parentheses

3x-9x-19-29=0

We add all the numbers together, and all the variables

-6x-48=0

We move all terms containing x to the left, all other terms to the right

-6x=48

x=48/-6

x=-8

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