6+2(3x-2)=-4(2+1x)

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Solution for 6+2(3x-2)=-4(2+1x) equation: 



6+2(3x-2)=-4(2+1x)

We move all terms to the left:

6+2(3x-2)-(-4(2+1x))=0

We add all the numbers together, and all the variables

2(3x-2)-(-4(x+2))+6=0

We multiply parentheses

6x-(-4(x+2))-4+6=0



We calculate terms in parentheses: -(-4(x+2)), so:

-4(x+2)

We multiply parentheses

-4x-8

Back to the equation:

-(-4x-8)



We add all the numbers together, and all the variables

6x-(-4x-8)+2=0

We get rid of parentheses

6x+4x+8+2=0

We add all the numbers together, and all the variables

10x+10=0

We move all terms containing x to the left, all other terms to the right

10x=-10

x=-10/10

x=-1

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