3(1n+2)=9(6-n)

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Solution for 3(1n+2)=9(6-n) equation: 



3(1n+2)=9(6-n)

We move all terms to the left:

3(1n+2)-(9(6-n))=0

We add all the numbers together, and all the variables

3(n+2)-(9(-1n+6))=0

We multiply parentheses

3n-(9(-1n+6))+6=0



We calculate terms in parentheses: -(9(-1n+6)), so:

9(-1n+6)

We multiply parentheses

-9n+54

Back to the equation:

-(-9n+54)



We get rid of parentheses

3n+9n-54+6=0

We add all the numbers together, and all the variables

12n-48=0

We move all terms containing n to the left, all other terms to the right

12n=48

n=48/12

n=4

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