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(7x+9)(5x+4)=0
We multiply parentheses ..
(+35x^2+28x+45x+36)=0
We get rid of parentheses
35x^2+28x+45x+36=0
We add all the numbers together, and all the variables
35x^2+73x+36=0
a = 35; b = 73; c = +36;
Δ = b2-4ac
Δ = 732-4·35·36
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(73)-17}{2*35}=\frac{-90}{70} =-1+2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(73)+17}{2*35}=\frac{-56}{70} =-4/5 $
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