3(1/5+x)=2(x+42)

Solution for 3(1/5+x)=2(x+42) equation:

3(1/5+x)=2(x+42)

We move all terms to the left:

3(1/5+x)-(2(x+42))=0


Domain of the equation: 5+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-5

x!=-5/1

x!=-5

x∈R


We add all the numbers together, and all the variables

3(+x+1/5)-(2(x+42))=0

We multiply parentheses

3x-(2(x+42))+1/5*3=0

We multiply all the terms by the denominator


3x*5*3-((2(x+42)))*5*3+1=0

Wy multiply elements

45x*3-((2(x+42)))*5*3+1=0

Wy multiply elements

135x-((2(x+42)))*5*3+1=0

We move all terms containing x to the left, all other terms to the right

135x-((2(x+42)))*5*3=-1