3(1/3x-12)=7x+6

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Solution for 3(1/3x-12)=7x+6 equation: 



3(1/3x-12)=7x+6

We move all terms to the left:

3(1/3x-12)-(7x+6)=0



Domain of the equation: 3x-12)!=0

x∈R



We multiply parentheses

3x-(7x+6)-36=0

We get rid of parentheses

3x-7x-6-36=0

We add all the numbers together, and all the variables

-4x-42=0

We move all terms containing x to the left, all other terms to the right

-4x=42

x=42/-4

x=-10+1/2

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