1/8(1-y)-1/10(2-y)-1/12(3+y)=0

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Solution for 1/8(1-y)-1/10(2-y)-1/12(3+y)=0 equation: 



1/8(1-y)-1/10(2-y)-1/12(3+y)=0



Domain of the equation: 8(1-y)!=0

y∈R





Domain of the equation: 10(2-y)!=0

y∈R





Domain of the equation: 12(3+y)!=0

y∈R



We add all the numbers together, and all the variables

1/8(-1y+1)-1/10(-1y+2)-1/12(y+3)=0

We calculate fractions


(120y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3))+(-96y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3))+(-80y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3))=0



We calculate terms in parentheses: +(120y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3))+(-96y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3))+(-80y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3)), so:

120y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3))+(-96y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3))+(-80y^2(-)/(8(-1y+1)*10(-1y+2)*12(y+3)

We can not solve this equation

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