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3(1/3x+2)-2(x-4)=13
We move all terms to the left:
3(1/3x+2)-2(x-4)-(13)=0
Domain of the equation: 3x+2)!=0We multiply parentheses
x∈R
3x-2x+6+8-13=0
We add all the numbers together, and all the variables
x+1=0
We move all terms containing x to the left, all other terms to the right
x=-1
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