(1/7x)-14=(3/14x)+21

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Solution for (1/7x)-14=(3/14x)+21 equation: 



(1/7x)-14=(3/14x)+21

We move all terms to the left:

(1/7x)-14-((3/14x)+21)=0



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 14x)+21)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/7x)-((+3/14x)+21)-14=0

We get rid of parentheses

1/7x-((+3/14x)+21)-14=0

We calculate fractions


14x/98x^2+(-((+3*7x)/98x^2-14=0

We calculate fractions

We do not support expression: x^4

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