3(1-x)-(x+2)=5+8(x-2)

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Solution for 3(1-x)-(x+2)=5+8(x-2) equation: 



3(1-x)-(x+2)=5+8(x-2)

We move all terms to the left:

3(1-x)-(x+2)-(5+8(x-2))=0

We add all the numbers together, and all the variables

3(-1x+1)-(x+2)-(5+8(x-2))=0

We multiply parentheses

-3x-(x+2)-(5+8(x-2))+3=0

We get rid of parentheses

-3x-x-(5+8(x-2))-2+3=0



We calculate terms in parentheses: -(5+8(x-2)), so:

5+8(x-2)

determiningTheFunctionDomain
8(x-2)+5

We multiply parentheses

8x-16+5

We add all the numbers together, and all the variables

8x-11

Back to the equation:

-(8x-11)



We add all the numbers together, and all the variables

-4x-(8x-11)+1=0

We get rid of parentheses

-4x-8x+11+1=0

We add all the numbers together, and all the variables

-12x+12=0

We move all terms containing x to the left, all other terms to the right

-12x=-12

x=-12/-12

x=1

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