3(x-2)+2(x-4)=1

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Solution for 3(x-2)+2(x-4)=1 equation: 



3(x-2)+2(x-4)=1

We move all terms to the left:

3(x-2)+2(x-4)-(1)=0

We multiply parentheses

3x+2x-6-8-1=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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