3(1-2z)=2(1+2z)

Solution for 3(1-2z)=2(1+2z) equation:

3(1-2z)=2(1+2z)

We move all terms to the left:

3(1-2z)-(2(1+2z))=0

We add all the numbers together, and all the variables

3(-2z+1)-(2(2z+1))=0

We multiply parentheses

-6z-(2(2z+1))+3=0


We calculate terms in parentheses: -(2(2z+1)), so:

2(2z+1)

We multiply parentheses

4z+2

Back to the equation:

-(4z+2)


We get rid of parentheses

-6z-4z-2+3=0

We add all the numbers together, and all the variables

-10z+1=0

We move all terms containing z to the left, all other terms to the right

-10z=-1

z=-1/-10

z=1/10