3(2x+1)+2(3x-4)=19

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Solution for 3(2x+1)+2(3x-4)=19 equation: 



3(2x+1)+2(3x-4)=19

We move all terms to the left:

3(2x+1)+2(3x-4)-(19)=0

We multiply parentheses

6x+6x+3-8-19=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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