3(1-2y)+7=-5(2y-3)-8

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Solution for 3(1-2y)+7=-5(2y-3)-8 equation: 



3(1-2y)+7=-5(2y-3)-8

We move all terms to the left:

3(1-2y)+7-(-5(2y-3)-8)=0

We add all the numbers together, and all the variables

3(-2y+1)-(-5(2y-3)-8)+7=0

We multiply parentheses

-6y-(-5(2y-3)-8)+3+7=0



We calculate terms in parentheses: -(-5(2y-3)-8), so:

-5(2y-3)-8

We multiply parentheses

-10y+15-8

We add all the numbers together, and all the variables

-10y+7

Back to the equation:

-(-10y+7)



We add all the numbers together, and all the variables

-6y-(-10y+7)+10=0

We get rid of parentheses

-6y+10y-7+10=0

We add all the numbers together, and all the variables

4y+3=0

We move all terms containing y to the left, all other terms to the right

4y=-3

y=-3/4

y=-3/4

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