3(6x-7)-12=5(x-4)

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Solution for 3(6x-7)-12=5(x-4) equation: 



3(6x-7)-12=5(x-4)

We move all terms to the left:

3(6x-7)-12-(5(x-4))=0

We multiply parentheses

18x-(5(x-4))-21-12=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We add all the numbers together, and all the variables

18x-(5x-20)-33=0

We get rid of parentheses

18x-5x+20-33=0

We add all the numbers together, and all the variables

13x-13=0

We move all terms containing x to the left, all other terms to the right

13x=13

x=13/13

x=1

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