3(1-2n)+8=(n-4)-43

Solution for 3(1-2n)+8=(n-4)-43 equation:

3(1-2n)+8=(n-4)-43

We move all terms to the left:

3(1-2n)+8-((n-4)-43)=0

We add all the numbers together, and all the variables

3(-2n+1)-((n-4)-43)+8=0

We multiply parentheses

-6n-((n-4)-43)+3+8=0


We calculate terms in parentheses: -((n-4)-43), so:

(n-4)-43

We get rid of parentheses

n-4-43

We add all the numbers together, and all the variables

n-47

Back to the equation:

-(n-47)


We add all the numbers together, and all the variables

-6n-(n-47)+11=0

We get rid of parentheses

-6n-n+47+11=0

We add all the numbers together, and all the variables

-7n+58=0

We move all terms containing n to the left, all other terms to the right

-7n=-58

n=-58/-7

n=8+2/7