7x-2(2x+3)=8-(3x-10)

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Solution for 7x-2(2x+3)=8-(3x-10) equation: 



7x-2(2x+3)=8-(3x-10)

We move all terms to the left:

7x-2(2x+3)-(8-(3x-10))=0

We multiply parentheses

7x-4x-(8-(3x-10))-6=0



We calculate terms in parentheses: -(8-(3x-10)), so:

8-(3x-10)

determiningTheFunctionDomain
-(3x-10)+8

We get rid of parentheses

-3x+10+8

We add all the numbers together, and all the variables

-3x+18

Back to the equation:

-(-3x+18)



We add all the numbers together, and all the variables

3x-(-3x+18)-6=0

We get rid of parentheses

3x+3x-18-6=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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